Factoring The Difference of 2 Squares
After studying this lesson, you will be able to:
- Factor the difference of two squares.
Steps of Factoring:
1. Factor out the GCF
2. Look at the number of terms:
- 2 Terms: Look for the Difference of 2 Squares
- 3 Terms: Factor the Trinomial
- 4 Terms: Factor by Grouping
3. Factor Completely
4. Check by Multiplying
This lesson will concentrate on the second step of factoring:
Factoring the Difference of 2 Squares.
**When there are 2 terms, we look for the difference of 2
squares. Don't forget to look for a GCF first.**
We have the difference of two squares when the following are
true:
There are 2 terms separated by a minus sign
Each of the term is a perfect square.
A partial list of perfect squares: 1, 4, 9, 16, 25, 36, 49,
64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400,
... it's a good idea to memorize as many of these as you can so
that you can recognize them in problems.
For a variable to be a square, it must have an even-numbered
exponent. For example, these are squares: x 2, x
4, a 10, x 2 y 8, x 2
y 4 z 2. These, however, are not squares:
x, x 3, y 5, x 2y, yz 3,
a 2 b 5c.
To factor the difference of 2 squares, we write 2 parentheses.
One will have an addition sign and the other will have a
subtraction sign like this:

Next, we find the square root of the first term. We put these
in the first positions. Then, we find the square root of the
constant term and we put these in the last positions.
Example 1
Factor x 2 - 64
There is no GCF other than one. So, we start with 2
parentheses. This is the difference of two squares because we
have 2 terms separated by a minus sign and because each term is a
perfect square. We start with the 2 parentheses and the signs.
Using the sign rule for the difference of 2 squares, we put in
one negative and one positive.

Now we take the square root of the first term. The square root
of x 2 is x so we put an x in the first positions:

Now we take the square root of the constant term. The square
root of 64 is 8 so we put an 8 in the last positions. Now, the
problem is completely factored.
(x + 8) (x - 8)
Check by using FOIL (x + 8) (x - 8) x 2 -8x + 8x
- 64 which is x 2 - 64
Example 2
Factor x 2 - 25
There is no GCF other than one. So, we start with 2
parentheses. This is the difference of two squares because we
have 2 terms separated by a minus sign and because each term is a
perfect square. We start with the 2 parentheses and the signs.
Using the sign rule for the difference of 2 squares, we put in
one negative and one positive.

Now we take the square root of the first term. The square root
of x 2 is x so we put an x in the first positions:

Now we take the square root of the constant term. The square
root of 25 is 5 so we put a 5 in the last positions. Now, the
problem is completely factored.
(x + 5) (x - 5)
Check by using FOIL (x + 5) (x - 5) x 2 - 5x +
5x - 25 which is x 2 - 25
Example 3
Factor 9x 2 - 100 y 2
There is no GCF other than one. So, we start with 2
parentheses. This is the difference of two squares because we
have 2 terms separated by a minus sign and because each term is a
perfect square. We start with the 2 parentheses and the signs.
Using the sign rule for the difference of 2 squares, we put in
one negative and one positive.

Now we take the square root of the first term. The square root
of 9 x 2 is 3x so we put a 3x in the first positions:

Now we take the square root of the constant term. The square
root of 100 y 2 is 10y so we put a 10y in the last
positions. Now, the problem is completely factored.
(3x + 10y) (3x - 10y)
Check by using FOIL (3x + 10y) (3x - 10y) 9x 2 - 30xy
+30xy - 100 y 2 whichis 9x 2 - 100 y 2
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